I was sent a load of mp3's by a friend and they all have "_20"  where i would expect the spaces to be.

Is there a script i can use to fix this?

Can i write my own? I don't know any scripting languages, only C.

Please help!!

Code: Select all

#!/bin/bash
while [ "$1" != "" ] ; do
        INFILE="$1"
        OUTFILE="`echo $INFILE | sed 's/_20/ /'`"
        mv "$INFILE" "$OUTFILE"
        shift
done


should do the trick. Start it with <1st mp3> <2nd mp> etc.. (e.g.: ./replace20 *.mp3)
If you get an argument list too long error, use xargs: ls -1 | xargs ./replace20

Ok, that's awesome, thanks.

When I say a load, I mean 60 so is there a way to get it to do the contents of a folder?

Not that I don't lore you for the script 

pingbat wrote:When I say a load, I mean 60 so is there a way to get it to do the contents of a folder?

Alanceil's script is doing this already.

Sure. Just start it with the folder's name: ./replace20 /home/tux/mp3/convertme/*.mp3

Note: You might want to add a g to the sed command:  sed 's/_20/ /g'
This will convert any occurence of _20 to a " ". Without the g, only the first _20 will be changed.