Registered Member
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I must be missing something...
I've been trying to setup the windows-menu key to bring up Lancelot (not the ordinary windows-logo one - AKA as meta, I mean the one with the picture of a menu+pointer). I have keycode 117 = F14 in my .xmodmap file, and am launching xmodmap using a bash-script in ~/.kde4/Autostart. Lancelot recognizes the key when using the "Configure shortcuts" menu, but it doesn't bring up the interface when hitting that key. If I configure it in "Global keyboard shortcuts" I can make the key bring up the interface but only screen-centered. I would like the interface to show up under they icon (I have in a panel on the top), just as if I had clicked the icon. Is that possible? If so, how? It does work using kickoff, but I very much prefer Lancelot. Any ideas?
OpenSUSE 11.4, 64-bit with KDE 4.6.4
Proud to be a member of KDE forums since 2008-Oct. |
KDE Developer
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It is the default behaviour to show L centered when invoked by a shortcut.
You can achieve the thing you want by a small work-around: 1. Open System Settings 2. Computer Administration -> Input actions 3. Create a new action named Lancelot (or something) 4. Set the key, and set the action command to: qdbus org.kde.lancelot /Lancelot show 1440 900 (replace the 1440 900 with the coordinates of your corner) Cheerio! |
Registered Member
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Ah, yes. That worked! Only question is...why didn't I think of that myself...?
OpenSUSE 11.4, 64-bit with KDE 4.6.4
Proud to be a member of KDE forums since 2008-Oct. |
KDE Developer
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KDE Developer
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Just an addition for the "open lancelot where icon in panel is" - now, if you want to do this, you just need to right-click the lancelot's icon in the panel -> choose Lancelot Launcher Settings -> Keyboard Shortcut -> and choose the key you want to use to invoke L.
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