|   Registered Member   
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							Documentation on 'reverse' is lacking regarding whether it does in-place reverse or not. I have a VectorXd called e.g. test and is filled with 5 numbers, from 1 to 5: 1 2 3 4 5 This does nothing: test.reverse(); This however does something: test = test.reverse(); 5 4 3 4 5 This looks like in-place reversing that doesn't use intermediate storage. Do I always have to put the output of reverse into a new vector or is there a simple way to get a vector reversed without doubling the storage? | 
|   Registered Member   
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							Solved it by doing it with a temporary vector... VectorXd tmp = test.reverse(); test = tmp; | 
|   Moderator   
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							well, the documentation says: Returns: an expression of the reverse of *this. So just like any other functions (transpose, normalize, adjoint, replicate) it's clear that it does nothing until the expression gets assigned to another object. http://eigen.tuxfamily.org/dox/classEig ... ce4b4649e2 There is also a reverseInPlace() function. | 
|   Registered Member   
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